Question

Determine the number nearest to 100000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21

Answer 1

The answer is 100800.

thank u

Answer 2

Answer:

Step-by-step explanation:

The number which is divisible by 8,15 and 21 is also divisible by the LCM of the number

The LCM of 8, 15 and 21 is

8= 2*2*2

15=3*5

21=3*7

LCM=2*2*2*3*5*7=840

If we divide 110000 00 by 840 we will get 800 as remainder

Does the number nearest to 110000 but greater than 10000 which is exactly divisible by 8 15 and 21 is

=110000-800

=109200

Hans 109200 is exactly divisible by 8, 15 and 21