Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15and 21.
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lcm of 8, 15, 21 is = 840
119 x 840 = 99960 < 100000
120x 840 = 100800 nearest to 100000
130 x840 =109200 nearest to 110000 [ 131x840=110040 >110000 ]
SO CORRECT NUMBER NEAREST TO 110000IS = 109200
119 x 840 = 99960 < 100000
120x 840 = 100800 nearest to 100000
130 x840 =109200 nearest to 110000 [ 131x840=110040 >110000 ]
SO CORRECT NUMBER NEAREST TO 110000IS = 109200
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