Question

Determine the number of atoms of nitrogen present in 3.00 moles N203​

Answer 1

Answer:

.5 mole of Nitrogen

   1 mole of N=14 gram

    0.5 mole N=0.5×14

=7gram

=  

2

1

​  

mole

                                   =  

2

1

​  

×6.022×10  

23

atoms

                                    =3.011×10  

23

atoms. (c) 8 gram O =?

     16 gram of O =1mole

     1 gram of O =  

16

1

​  

mole

      8 gram of O =  

16

1

​  

×8=  

2

1

​  

 

                          =  

2

1

​  

×6.022×10  

23

atoms

=3.011×10  

23

atoms.

 

 Same as in O,S mole of nitrogen.

Explanation: