Determine the number of bit strings of length 10 that either begin with three 0'S or end with two 1's
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Step-by-step explanation:
String of length 10 that begin with 0's
There are two possible bits :0 and 1
First digit =1 way ( has to be 0)
Second digit =1 way( has to be 0)
Third digit =1 way (has to be 0)
Fourth digit =2 ways
Fifth digit =2ways
Sixth digit =2 ways
Seventh digit =2 ways
Eight digit =2ways
ninth digit =2 ways
Tenth digit =2ways
Use the product rule :
1.1.1.2.2.2.2.2.2.2=2^7
=128
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