Determine the number of electrons ,protons and neutrons present in the following atoms
(6 M)
1. 88Ra226 2. 73 Ta 181
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Answer: In Ra electrons=88, protons=88, neutrons= 118
In Ta electrons= 73, protons=73, neutrons= 108
Explanation: Atomic no. (Z)= No. of protons in an atom
Atomic mass (A)= No. of protons + No. of neutrons
and number of electrons in an atom is = No. of protons.
1. In Ra (z)= 88
A= 226-88= 118
2. In Ta (Z) = 73
A= 181-73= 108
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