Question

Determine the number of moles in 0.55 mg of electrons

Answer 1

Answer:

1.0034793

Explanation:

1kg=106mg Mass of an electron=9.1×10-31kg

=9.1×10-25mg

next, number of electron (x) present in 0.55mg

:

0.55/(9.1×10-25)=0.604×1024

further

no of moles(n)=x/nX/n

'n' is Avogadro's constant.

n=0.694×1024/(6.023×1023)=1.0034793

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Answer 2

Hi, please consider the answer given below

In the detrmination of the number of bromide ions in 0.2 mole of MgBr2

We use the avogadros number 6.02 x 10^23

Number of molecules of bromide ions= No. of moles x Avogadros number

Number of molecules of bromide ions= 0.2 x (6.02 x 10^23)

= this gives 1.2 x 10^23 bromide ions