Determine the number of moles in 100g Fe(OH)3 and 50g Ba(NO3) 2.
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Answer:
Given mass of Fe(OH)3 =100g
Molar mass of Fe(OH)3 = 55 + 16x3 + 1 x3
= 55+48+3
= 106 g / mol
Mole = given mass /molar mass
= 100 / 106
= 50/53 moles
2. given mass of Ba(NO3)2 = 50g
molar mass of Ba (NO3)2 = 137 +14x2 +48x2 = 137+28+96
= 261 g/mol
mole = 50 /261 mol
I hope it's a right answer.
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