Question

Determine the number of moles of O in 10.6g of NaCO2

Answer 1

Answer:

The molar mass of sodium carbonate Na2CO3 is 106g, so 10.6g is 10.6/106 = 0.1mol.

Therefore, there are 0.1 “mol” of 3 x O (“mol” in quotation, meaning that oxygen is not present in the molecular state, but as atoms bonded to the carbon).

So, we have 3 x 0.1mol = 0.3mol of oxygen atoms, or 0.3 x 16 = 4.8g of oxygen.

If you want to consider this as “mol” of O2 (which is incorrect and frankly, woolly thinking!), it would

be 1.5 x 0.1mol = 1.5mol of O2.

Explanation:

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