Question

determine the number of moles present in 0.55mg of electrons
a-1mol
b-2mol
c-1.5 mol
d-0.5 mol​

Answer 1

Answer:

Mass of e

−

=9.1×10

−31

kg

So 9.1×10

−31

×10

6

mg contains 1e

−

or 1mg contains

9.1×10

−31

×10

6

1

e

−

so 0.55 mg contains

9.1×10

−25

1

×0.55e

−

=6.043×10

23

e

−

Now simply apply avogadro's law

6.023×10

23

e

−

make 1 mole

so 1 mole ⇒ Ans

Answer 2

Answer:

0.5 is the correct answer

Explanation:

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