Question

Determine the number of moles present in 0.55mg of electrons Options 1) 1 mole 2) 2 mole 3)3 mole 4) 0.5 mole

Answer 1

Number of electron= 9.1*10^-31 Kg = 9.1*10^-25 mg

Number of electron present in 0.55 mg

=0.55/9.1*10^-25

=0.604 * 10^24

Number of moles = Number of electron/Avogadro number

= 0.604 *10^24 / 6.023 * 10^23

= 1.0034 mol