Question

determine the number of permutations of the letters of the word "HALLUCINATIONS"

Answer 1

Solution :-

» First of all in "HALLUCINATIONS" there are 14 letters.

» So to arrange n things in n ways = n!

» So total number of ways Permutation of 14 letters = 14!

♦Now there is repetition of some letters

A :- Two times

L :- Two times

I :- Two times

N :- Two times

♦So for each n letter repetition we will divided it by n!

Then for

A = 2!

L = 2!

I = 2!

N = 2!

♦ So total number of ways

$=\dfrac{14!}{2! \times 2! \times 2! \times 2! }$

$= \dfrac{14!}{2 \times 2 \times 2 \times 2 }$

$= \dfrac{14!}{2^4}$

Answer 2

Step-by-step explanation:

How many ways can 8 couple be seated in a row if each couple is seated together?