Question

determine the number of water molecules in 0.2830 g Na2CO3.10H2O​

Answer 1

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Explanation:

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Answer 2

Answer :

The number of water molecules in 0.2830 g of Na2CO3. 10 H20 is 5.90× 10 ^21.

Explanation :

The molecular weight of each atom is

Na = 23 g

C = 12 g

O = 16 g

H = 1 g

So, the molecular weight of the given compound is 286 g / mol

Calculating Number of moles =

$number \: of \: moles = \frac{given \: mass \: }{molecular \: weight} = \frac{0.2830}{286} = 9.8 \times {10}^{ - 4}$

No, number of molecules in 0.2830 g = 9.8 × 10^(-4) × 6.022 × 10^23 = 59.0156 × 10^19

Now, since there are 10 molecules of H2O we have :

Number of water molecules = 5.90×10^21 molecules .

Concept :

• The SI base unit of material amount is the mole, denoted by the sign mol.
• How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that material is a mole.
• An elementary entity can be an atom, a molecule, an ion, an ion pair, or a subatomic particle like an electron depending on what the substance is.
• Exact 6.02214076 × 10^23 basic entities make up the mole.

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