Math, asked by hemantgupta69, 10 months ago

. Determine the number of zeros of the polynomial x^4-1.​

Answers

Answered by Anonymous
8

Answer:

p(x) = x^4-1

x^4-1 =0

x^4= 1

x =1

Answered by harendrachoubay
3

The number of zeros of the given polynomial is 2.

Step-by-step explanation:

The given polynomial:

x^{4}-1

To find, the number of zeros of the given polynomial = ?

x^{4}-1

=(x^{2})^2-(1^{2})^2

Using the algebraic identity,

a^{2}-b^{2}=(a+b)(a-b)

=({x^{2}+1^{2})(x^{2}-1^{2})

=(x^{2}+1)(x+1)(x-1)

x = 1 and - 1

x^2+1 is no real roots.

The number of zeros of the given polynomial = 2

Hence, the number of zeros of the given polynomial is 2.

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