Question

Determine the oxidation number of manganese in the products as per given equation. H+ + 2H2O + 2 MnO4^- + 5SO2 gives Products (in acidic solution)

Answer 1

the answer is 2 but i don't know how.

Hope it helps you............

Answer 2

Answer:

+2

Explanation:

The equation of the reaction of permangante ion and sulfur dioxide is shown below as:

$2MnO_4^- + 5SO_2 + 2H_2O\rightarrow 2Mn^{2+} + 5SO_4^{2-} + 4 H^+$

In the reaction above,

$MnO_4^-$ is being reduced to $Mn^{2+}$

$SO_2$ is being oxidized to $SO_4^{2-}$

Product = $Mn^{2+}$

Oxidation state of $Mn$ in $Mn^{2+}$ is +2