Question

Determine the oxidation number of N in NH4HCO3

Answer 1

Answer:

The oxidation of nitrogen in NH4+ is -3. The hydrogen atoms have +1 and there are four of them. And net charge on the molecule is +1. Let nitrogen's oxidation state be x. Therefore, (4×(+1)) + x = +1. Hence, x is -3.

The oxidation number nitrogen of NO3- is +5. The oxygen atoms have -× and there are 3 of them. And net charge on the molecule is -1. Let the oxidation state of nitrogen be x. Therefore, (3×(-2)) + x = -1. Hence, x = +5. For numerical purposes however, we can assume that each nitrogen is in +1 and overall oxidation state of nitrogen +2.

Answer 2

The oxidation number of N in $NH_4HCO_3$ is -3.

Given:

$NH_4HCO_3$ is a nitrogenous compound.

To Find:

The oxidation number of N.

Solution:

$NH_4HCO_3$ can give rise to two ions $NH_4^+$ and $HCO_3^-$.

Let us assume the oxidation number of N in $NH_4HCO_3$ is x.

In $NH_4^+$ overall charge is +1 and the oxidation number of H is +1

So, x+(4×1)= 1

⇒x = -3

Hence, the oxidation number of N in $NH_4HCO_3$ is -3.

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