Determine the oxidation number of s in Na2S2O3
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Key points:
=> Alkali metals like Li, Na, K, Rb, etc always has a oxidation number +1
=> Alkali Earth Metals like Be, Mg, Ca, Sr, etc. always have a oxidation number +2
=> Fluorine always has a oxidation number -1
=> Oxygen mostly (not always) has a oxidation number -2
Answer:
Na has Oxdn number +1
Oxygeb has -2
total charge of Na2SO4 is 0
therefore,
2(On number of Na) + (on number of S) + 4(On of O) = 0
2(+1) + (x) + 4(-2) =0
=> 2 + x - 8 = 0
=> x - 6=0
=> x= +6
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