Question

Determine the p.d. which must be applied to a 2 k resistor in order that a current

of 10 mA may flow.​

Answer 1

Answer:

20V

Explanation:

V=IR = 10mA × 2kohms = 10×10^(-3)×2×10³

=20V

Answer 2

Explanation:

Resistance R = 2 kΩ = 2 × 103 Ω = 2000 Ω

Current I = 10mA = 10 × 10-3 A = 0.01 A

From Ohm’s law, potential difference is

V = IR = (0.01) (2000) = 20 V