Physics, asked by abhaynirmalan, 9 months ago

Determine the p.d which
must be applied
to a 2k ohm
resistor in order that a current
of 10mA
may flow​

Answers

Answered by wanimustafai
2

Answer: V= IR Where I= 10mA= 10/1000=1/100= 0.01 ,R= 2 ohm V=IR V= 0.01 × 2 V= 0.02voltsPlease

Answered by anshpurohit77
0

Answer:

20v

Explanation:

v=ir this implies that v equals to 0.01A×2000ohm=20v

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