Determine the pahse of water at T=260 degree celcius p=5 Mpa T= 2 degree celcius P=100Kpa
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Answer:
p¹/t¹ = p²/t²
5/260=100/t2
T = 1.67
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Determine the phase of the water at temperature and pressure .
Take the saturated pressure value from the table “Properties of saturated water-temperature tables, table B.1.1” recorded at a temperature of .
Since , the phase is .
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