Question

Determine the percent
decrease in
the acceleration due to earth's gravity at a
point 0.6R below the earth's surface R-
Radius of earth.​

Answer 1

solution;-

• At what height the acceleration due to gravity will be reduced to 36% of its value on the surface of the earth? A ... R= radius of the earth. At the height h from earths surface acceleration due to gravity g1 is g1=(R+h)2GM​. From above ... Derive an expression for acceleration due to gravity of depth'd' below the earth's surfaces

PRACTICAL SOLUTION-;

g=g(1−  

R

2h

​

)

g

g

​

=1−  

6400

2×64

​

=1−  

6400

128

​

 

for %R change

1−  

g

g

​

=1−1+  

6400

128

​

 

g

g−g

​

=  

6400

128

​

=0.02

% change =0.02×100=2%

#official Nazo.