Question

Determine the percent of increase or decrease.
1. Php 100.00 to Php 300.00
2. 150kgs to 145 kgs
3. 40kms to 72kms
4.36 m to 26 m
s. inches to 15 indhofULLDOCUBE
6. 1.5 liters to 2 liters
Solve the following
7. Maria was given Php 156.00 discount on a pair of shoes
marked Php 1,200.00. How much was the discount rate and
the selling price?
8. Andrea,s pulse rate changed from 70 to 90 after
exercising. What is the percent of increase?
9. Paul bought a toy worth Php 180.00 without VAT. If he
paid 12% VAT. How much did he pay in all?
10. Lina earned a 10-peso interest in 3 months on her
1,000-peso savings. What was the rate of interest per
year?​

Answer 1

Answer:

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Step-by-step explanation:

Answer:

(512)^{-\frac{2}{9}}=\frac{1}{4}(512)−92=41

Step-by-step explanation:

Given : Expression (512)^{-\frac{2}{9}

To find : The value of the expression ?

Solution :

First we factor 512 so that we get to convert it into the power,

512=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2512=2×2×2×2×2×2×2×2×2

512=2^9512=29

Substitute in expression,

(512)^{-\frac{2}{9}}=(2^9)^{-\frac{2}{9}}(512)−92=(29)−92

(512)^{-\frac{2}{9}}=(2)^{-\frac{2\times 9}{9}}(512)−92=(2)−92×9

(512)^{-\frac{2}{9}}=(2)^{-2}(512)−92=(2)−2

(512)^{-\frac{2}{9}}=\frac{1}{2^2}(512)−92=221

(512)^{-\frac{2}{9}}=\frac{1}{4}(512)−92=41