Question

Determine the percentage by mass of calcium in calcium carbonate (Ca=40).​

Answer 1

Answer:

40%

Explanation:

CaCO3 mass = 40 + 12 + 3(16) = 52 + 48 = 100

mass Ca = 40

%age = 40/100 * 100 = 40%

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Answer 2

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==>Let us now use this law to find the weight of the calcium in 4 g of calcium carbonate. The percentage compositions of the elements of calcium carbonate are given as: Ca = 40%; C = 12%; O = 48%.

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==>Correct option is

A

40

Molecular mass of CaCO 3

=40+12+3×16=100 amu

Mass of calcium in 1 mole of CaCO 3

= 40 gm

Percentage of calcium =

100

40

×100=40%

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