Determine the pH of 10-2 M NaOH solution.
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HEY FOLK...
[OH−] = [NaOH] = 10⁻² M
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[OH−] = [NaOH] = 10⁻² M
At room temperature, you have
KW=10⁻¹⁴This means that the concentration of hydronium ions can be determined by using
[H3O+]=KW[OH−]Plug in your values to get
[H3O+] = 10⁻¹⁴/ 10⁻² = 10⁻¹²MThe pH of the solution is equal to
pH=−log([H3O+])In your case,
pH = −log(10⁻¹²) = 12HOPE IT HELPS...
#Mme
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