Chemistry, asked by narendrajoshi859, 1 year ago

Determine the pH of 10-2​ M NaOH solution.

Answers

Answered by Anonymous
18
HEY FOLK...


[OH−]
= [NaOH] = 10⁻² M


KW=[OH−][H3O+]

At room temperature, you have

KW=10⁻¹⁴

This means that the concentration of hydronium ions can be determined by using

[H3O+]=KW[OH−]

Plug in your values to get

[H3O+] = 10⁻¹⁴/ 10⁻² = 10⁻¹²M

The pH of the solution is equal to

pH=−log([H3O+])

In your case,

pH = −log(10⁻¹²) = 12




HOPE IT HELPS...

#Mme
Answered by satwikBera
3

Answer:

I hope it will help you.

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