Determine the ph of 5.4×10^-4M Hcl ?
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Answer:
Strong base so,
pOH = -log[NaOH] = -log(0.0004)=-log(1x10-4)=4.0 pH = 14.0-pOH = 14.0 – 4.0 = 10.0
(makes sense since we expect basic solution).
Mark as brainlist answer.
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