Question

determine the ph of a solution of potassium hydroxide with a concentration of 0.000357​

Answer 1

Explanation:

Potassium hydroxide fully ionizes when dissolved in water according to the following equation:

KOH ----> K+ + OH-

1:1 ratio = KOH = [OH] - = 3.57 × 10^-4

[H3O} + = Kw/[OH]- = 1.0 x 10^-14/ 3.57 × 10^-4 = 0.28 x 10^-10 = 2.8 x 10^-11

Now, after finding the concentration of the hydronium ion, the pH of the solution is determined:

pH = -log[H3O]

     = -log[2.8 x 10^-11] = 10.55