Determine the point from the graph of linear equation 2x + 5y = 21 whose abscissa is twice
of its ordinate.
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1
Answer:
Point=(7/3,14/3)
Step-by-step explanation:
2x+5y=21
Abscissa=x
Ordinate=y
Given:- Absiscaa=2(ordinate)
x=2y
2x+5y=21
2(2y)+5y=21
9y=21
y=21/9
y=7/3
x=2y=14/3
(x,y)=(7/3,14/3)
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