Determine the point on graph of linear equation 2 X + 5y = 19 whose ordinate is 1 1/2 it abscissa
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YO,
Given linear equation is 2x + 5y = 19 … (1)
Given that ordinate is 1 ½ times its abscissa
That is y = 3x /2
Hence equation (1) becomes
2x + 5(3x /2) = 19
19x/2 = 19
Therefore, x = 2
y = 3x/2 = (3 × 2)/2 = 3
Thus the point on the graph is (2, 3).
HOPE IT HELPS!!
Given linear equation is 2x + 5y = 19 … (1)
Given that ordinate is 1 ½ times its abscissa
That is y = 3x /2
Hence equation (1) becomes
2x + 5(3x /2) = 19
19x/2 = 19
Therefore, x = 2
y = 3x/2 = (3 × 2)/2 = 3
Thus the point on the graph is (2, 3).
HOPE IT HELPS!!
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