Determine the point on the graph of the equation 3x + 5y = 25 whose x-coordinate is 5 upon3 times its ordinate.
Also, find the points where the given line cuts the x-axis and y-axis.
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Step-by-step explanation:
Substitute this X=5/3Y in 3X+5Y=25
3(5/3Y) +5Y =25
5Y+5Y=25
10Y=25
Y=5/2
THEN X=5/3Y = 5/3 * 5/2 =25/6
So the point is (25/6 , 5/2)
And line meet X axis at Y=0
3X +5 *0 =25
X=25/3
LINE MEET X-AXIS AT (25/3 , 0)
line meet Y axis at X=0
3*0 + 5Y=25
Y=25/5 = 5
Line meet Y axis at (0,5)
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