Math, asked by jiyawalia15, 8 months ago

Determine the point on the graph of the equation 3x + 5y = 25 whose x-coordinate is 5 upon3 times its ordinate.
Also, find the points where the given line cuts the x-axis and y-axis.
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Answers

Answered by shivanibollam22
0

Step-by-step explanation:

Substitute this X=5/3Y in 3X+5Y=25

3(5/3Y) +5Y =25

5Y+5Y=25

10Y=25

Y=5/2

THEN X=5/3Y = 5/3 * 5/2 =25/6

So the point is (25/6 , 5/2)

And line meet X axis at Y=0

3X +5 *0 =25

X=25/3

LINE MEET X-AXIS AT (25/3 , 0)

line meet Y axis at X=0

3*0 + 5Y=25

Y=25/5 = 5

Line meet Y axis at (0,5)

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