determine the point on the graph of the linear equation 2 X + 5 Y equal to 19 whose ordinate is 3/2 times its abscissa
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Let the abscissa be x.
Then the ordinate = 3/2a .
Now, Coordinates of the point ( a, 3/2a ) .
Also, Given that it is a point on the line 2x + 5y = 19
Now,
2(a) + 5(3/2a) = 19
2a + 15/2a = 19
19a = 38
a = 2 .
Now, Abscissa = 2 .
Ordinate = 3/2(2)= 3 .
\bold{ The \: required \: point \: is \: ( 2 , 3 )}Therequiredpointis(2,3)
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