Math, asked by royniraj17, 1 year ago

determine the point on the graph of the linear equation 2 X + 5 Y equal to 19 whose ordinate is 3/2 times its abscissa​

Answers

Answered by jyotirkmourya474
3

Answer:

Let the abscissa be x.

Then the ordinate = 3/2a .

Now, Coordinates of the point ( a, 3/2a ) .

Also, Given that it is a point on the line 2x + 5y = 19

Now,

2(a) + 5(3/2a) = 19

2a + 15/2a = 19

19a = 38

a = 2 .

Now, Abscissa = 2 .

Ordinate = 3/2(2)= 3 .

\bold{ The \: required \: point \: is \: ( 2 , 3 )}Therequiredpointis(2,3)

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