Determine the point on the graph of the linear equation 2x+5y=19, whose ordinate is 3/2 times it's abscissa
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Определите точку на графике линейного уравнения 2x+5y=19, ордината которой равна 3/2 раз ее абсциссе
Step-by-step explanation:
У=3\2*х , у-1,5х.
2x+5y=19 , 2x+1,5х=19 ,3,5х=19 , х=19:1,5 , х=190\15=38\3.
У=3\2*38\3=38\2=19 .
А(38\3 ;19)
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