Question

Determine the point on the graph of the linear equation 2x+5y=19,whose ordinate is 1 and half times its abscissa

Answer 1

Let the abscissa be x.
Then the ordinate = 3/2a .

Now, Coordinates of the point ( a, 3/2a ) .

Also, Given that it is a point on the line 2x + 5y = 19

Now,
2(a) + 5(3/2a) = 19

2a + 15/2a = 19

19a = 38

a = 2 .

Now, Abscissa = 2 .
Ordinate = 3/2(2)= 3 .

$\bold{ The \: required \: point \: is \: ( 2 , 3 )}$

Answer 2

hey mate ur answer is here.....
Mark me as the branliest ....