Determine the point on the graph of the linear equation 2x+5x=20 whose x coordinate is 5/2 times its ordinate
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Let the ordinate be y. Then the abcissa or x-cordinate is 5/2 * y.
Using the equation 2x+5y = 20 and putting value of x in it we get
2 * 5/2 * y + 5y = 20
=>10y =20=> y =2 ; x= 5/2 * y = 5/2 * 2 = 5
So the point (x,y) is (5,2)
Hope it helps. Mark it as the brainliest answer.
Using the equation 2x+5y = 20 and putting value of x in it we get
2 * 5/2 * y + 5y = 20
=>10y =20=> y =2 ; x= 5/2 * y = 5/2 * 2 = 5
So the point (x,y) is (5,2)
Hope it helps. Mark it as the brainliest answer.
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