Question

determine the point on the linear equation 2x+5y=19,whose ordinate is 1 1/2 times its abscissa​

Answer 1

Answer:

Let x be the abscissa of the given line 2x+5y=19, then by given condition,

Ordinate (y)=112×(y)=112× Abscissa

⇒ y=32x⇒ y=32x

On putting y=32xy=32x in given equation, we get

2x+5(32)x=192x+5(32)x=19

⇒ 4x+15x=19×2⇒ 4x+15x=19×2

⇒ 4x+15x=38⇒ 4x+15x=38

⇒ 19x=38⇒ 19x=38

⇒ x=3819⇒ x=3819

∴ x=2∴ x=2

On substituting the value of x in Eq. (i), we get

y=(3)/(2)xx2=3implies " " y=3`

Hence, the required point is (2,3).