Question

determine the point on the linear equation x+y=6,whose ordinate is twice its abscissa​

Answer 1

Answer:

MATHS

Determine the point on the graph of the linear equation 2x+5y=19, whose ordinate is 1

2

1

times its abscissa.

December 20, 2019avatar

Venkatesh Jaykumar

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ANSWER

Let the abscissa be a

Then ordinate =

2a

3

New coordinates of point is (a,

2a

3

)

Given that is a point on line 2x+5y=19

now

2(a)+5(

2a

3

)=19

2a+

2

15a

=19

4a+15a=38

19a=38

a=2

∴ abscissa =2

ordinate =

2

3(2)

=3

∴ the required point(2,3)

Solution :-