Question

determine the position, size and nature of the image of an object 4cm tall placed on the principal axis of focal length 15cm at a distance 30cm from the mirror ​

Answer 1

Step-by-step explanation:

ho = 4cm

f = 15

u = -30cm

By mirror formula = 1/f = 1/v+1/u

1/15 = 1/v+1/-30

1/v = 1/15+1/30

1/v = 3/30

v = 10cm

Magnification = -v/u = hi/ho

= -10/-30

= 1/3

1/3 = hi/4

hi = 1.33cm

Position = 10cm

Size = 1.33cm

Nature = Virtual and Erect and Diminished

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