Question

Determine the positive values of P for which equation

​x ^ 2 + 2 p x + 64 = 0 and x ^ 2 - 8 x + 2 p = 0

will both have real roots.​

Answer 1

Answer:

Hey

Here is your answer,

2x^2 +px+8=0

b^2-4ac=0

(P)^2 - 4x2x8=0

P^2-64=0

P^2=64

P=8

Hope it helps you!