Question

determine the power delivered by the current source of the circuit as shown in figure above​

Answer 1

Answer:

First we will find the equivalent resistance of the circuit.

The 7Ω and 5Ω are in series so equivalent is 7+5=12Ω.

12Ω and 6Ω are in parallel, so equivalent is 12×6/(12+6)=4Ω.

These 4Ω and 12Ω are in parallel, so their equivalent is 12×4/(12+4)=3Ω.

This 3Ω and 7Ω are in series so equivalent is 3+7=10Ω.

So the equivalent resistance of the circuit is R

eq

=10Ω.

Thus the power supplied is

R

eq

V

2

=60

2

/10=360