Physics, asked by 423prachisvjc, 7 months ago

Determine the pressure of oxygen at 0° c if the density of oxygen at stp = 1.44 kg / m³ and the RMS speed of molecules at stp = 456.4 m/s

Answers

Answered by tripathiakshita48
0

Answer:

Pressure of oxygen a 0° c = 39948 Pa

Explanation:

From the above question,

They have given :

The pressure of oxygen at 0° c if the density of oxygen at stp = 1.44 kg / m³ and the RMS speed of molecules at stp = 456.4 m/s

Here we have to find the pressure .

Using the ideal gas law, we can solve for the pressure of oxygen at 0° c:

PV = nRT

P = nRT / V

P = (1.44 kg/m³)*(4.56 m/s)*(8.314 J/mol*K)*(273 K) / (22.41 L/mol)

P = 11.8 atm

The equation for pressure is:

P = ρ x RMS speed²

P = (1.44 kg/m³) x (456.4 m/s)²

P = 3.03 x 10⁵ Pa

P = (1.44 kg/m³)(8.314 J/K*mol)(273.15 K)/(31.998 g/mol)

P = 21.75 kPa

At 0° C, the pressure of oxygen is 3.03 x 10⁵ Pa.

Pressure of oxygen a 0° c = 39948 Pa

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