Question

Determine the probability that a digit chosen at random from the digits 1, 2, 3, …12 will be odd.

Answer 1

Answer:

0.5

Step-by-step explanation:

Total odd no. = 1,3,5,7,9,11

probability of getting is no.= 6/12=0.5

Answer 2

Given:

Digits 1, 2, 3, …12.

To find:

The probability of getting odd when a digit is chosen at random.

Solution:

As we know that probability of getting an outcome B or P(B) is equal to the number of favourable outcomes or n(B) divided by a total number of outcomes or n.

This means

$P(B) = \frac{n(B)}{n}$

Now,

As given,

We have,

Digits 1, 2, 3, …12.

Here,

Total number of outcomes or n = 12

Odd digits = 1, 3, 5, 7, 9 and 11

So,

The number of favourable outcomes or odd digits = 6

So, the probability of getting odd when a digit is chosen at random

$= \frac{6}{12}$

$= \frac{1}{2}$

$= 0.5$

Hence, when a digit is chosen at random from digits 1, 2, 3, …12, the probability of getting odd is 0.5.