Math, asked by jayanthchennoju, 11 months ago

Determine the probability that a digit chosen at random from the digits 1, 2, 3, …12 will be odd.

Answers

Answered by summer2015514
8

Answer:

5/11

Step-by-step explanation:

no.of odd numbers=5

total no. of digits=12

probability=5/12

Answered by rahul123437
0

Probability

For finding the probability of choosing a digit randomly from 1, 2, 3, 4,5,6,7,8,9,10,11, 12, we need to follow the formula i.e.

probability = \frac{number \ of\  favourable\  outcome}{Total \ number\ of \ outcomes}

In this case favorable event is choosing the outcome,

So among given numbers,  odd numbers are 1,3,5,7,9,11.

So, number of occurrence of favorable outcome is 6.

Hence, probability is  \frac{6}{12}=\frac{1}{2}  .

So, probability that a digit chosen at random from digits will be odd is  1/2.

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