Determine the quadratic equation whose the product of root are 6/7 , -3
Answers
Answered by
0
Answer:
7x^2+15x-18=0
7x^2+21x-6x-18=0
7x(x-3)-6(x+3)=0
(x+3)=0 and (7x-6)=0
x=-3 and x=6/7
Attachments:
Similar questions