Question

Determine the radius of a braided mild steel rope in a crane used to lift 1000 metric tonnes load,given mild steel tensile strength=0.3GPa,g=10m/s²,considering a safety factor of 8​

Answer 1

Answer:

Formula: SWL (kg) = D2(mm) x 8

For example: Rope dia (D) = 12 mm SWL (kg) = D2 (mm) x 8 = D (mm) x D (mm) x 8 = 12 x 12 x 8 = 1152 kg SWL (t) = 1.15 tonnes The above equation can be reversed to calculate the diameter (D) in millimetres of FSWR needed to lift a given load.

Explanation: