Determine the range of the function (screenshot attached) PLEASE HELP!!!!!!!
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1929Consider f: R. → [-5, ∞) given by f(x) = 9x² + 6x-5. Show that f is invertible with the inverse f1 of given f by f1 (y) = (√y+6)-1 3 f(x) = 9x² + 6x-5 f is invertible if it is one-one and onto Rough One-one Steps: Checking one-one 1. Calculate f(x₁) f (x₁) = 9(x₁)² + 6x₁ - 5 2. Calculate f(x₂) f (x₂) = 9(x₂)² + 6x₂ - 5 3. Putting f(x₁) = f(x₂) we have to prove x₁ = X₂ Putting f (x₁) = f (x₂) 9(x₁)² + 6x₁5 = 9(x₂)² + 6x₂-5 9(x₁)29(x₂)² + 6x₁6x₂ = 5 + 5
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