Chemistry, asked by tahahusseinsocial, 8 months ago

Determine the rate of chemical reaction proceeding according to the scheme
3А + 2В  2С + 3Д. Concentration of substance А is 9.0 mol/l, of substance В is
0.6 mol/l, rate constant is 0.9 mol/lmin.

Answers

Answered by YQGW
0

Explanation:

the molar concentrations of reactants, and k is the rate constant, which is specific for a particular reaction at a particular temperature. The exponents m, n, and p are usually positive integers (although it is possible for them to be fractions or negative numbers). The rate constant k and the exponents m, n, and p must be determined experimentally by observing how the rate of a reaction changes as the concentrations of the reactants are changed. The rate constant k is independent of the concentration of A, B, or C, but it does vary with temperature and surface area.

The exponents in a rate law describe the effects of the reactant concentrations on the reaction rate and define the reaction order. Consider a reaction for which the rate law is:

rate

=

k

[

A

]

m

[

B

]

n

If the exponent m is 1, the reaction is first order with respect to A. If m is 2, the reaction is second order with respect to A. If n is 1, the reaction is first order in B. If n is 2, the reaction is second order in B. If m or n is zero, the reaction is zero order in A or B, respectively, and the rate of the reaction is not affected by the concentration of that reactant. The overall reaction order is the sum of the orders with respect to each reactant. If m = 1 and n = 1, the overall order of the reaction is second order (m + n = 1 + 1 = 2).

The rate law:

rate

=

k

[

H

2

O

2

]

describes a reaction that is first order in hydrogen peroxide and first order overall. The rate law:

rate

=

k

[

C

4

H

6

]

2

describes a reaction that is second order in C4H6 and second order overall. The rate law:

rate

=

k

[

H

+

]

[

OH

]

describes a reaction that is first order in H+, first order in OH−, and second order overall.

Similar questions