determine the ratio in which line 2x+y-4=0 divides the joining of (-2,2) , (3,7)
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Heya,
Let the line divided it in the ratio k : 1 .
Thus, by section formula,
Coordinate of the point which divides it in the ratio k : 1 is![x = \frac{3k - 2}{k + 1} \:and \: y = \frac{7k + 2}{k + 1} x = \frac{3k - 2}{k + 1} \:and \: y = \frac{7k + 2}{k + 1}](https://tex.z-dn.net/?f=+x+%3D+%5Cfrac%7B3k+-+2%7D%7Bk+%2B+1%7D+%5C%3Aand+%5C%3A+y+%3D+%5Cfrac%7B7k+%2B+2%7D%7Bk+%2B+1%7D+)
Now, this point will lies on the given line :-
![2( \frac{3k - 2}{k + 1} )\: + \: ( \frac{7k + 2}{k + 1} ) - 4 = 0 2( \frac{3k - 2}{k + 1} )\: + \: ( \frac{7k + 2}{k + 1} ) - 4 = 0](https://tex.z-dn.net/?f=+2%28+%5Cfrac%7B3k+-+2%7D%7Bk+%2B+1%7D+%29%5C%3A+%2B+%5C%3A+%28+%5Cfrac%7B7k+%2B+2%7D%7Bk+%2B+1%7D+%29+-+4+%3D+0)
Solving it, we get
K =![\frac{2}{9} \frac{2}{9}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B9%7D+)
So, ratio= K:1, i.e
Ans.
Thanks
KSHITIJ
Let the line divided it in the ratio k : 1 .
Thus, by section formula,
Coordinate of the point which divides it in the ratio k : 1 is
Now, this point will lies on the given line :-
Solving it, we get
K =
So, ratio= K:1, i.e
Thanks
KSHITIJ
anjalibonia79:
i don't think so cause my ans is 2\9
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