Question

determine the ratio in which the straight line x-y-2=0 divides the line segment joining (3,-1) and (8,9)

Answer 1

Determine the ratio In which the straight line x-y-2=0 divide the line segment joining (3,-10) and (8,9) ?

Solution :

Let A=(3,-10) and B=(8,9)

Let the line x-y-2=0 divides the line segment AB at point C(x,y) in the ratio m:n.

C(x,y)=[m*8+n*3/m+n,9m-10n/m+n]

8m+3n/m+n-9m-10n/m+n-2=0

8m+3n-9m+10n-2m-2n=0

-3m+11n=0

11n=3m

m/n=11/3

Hence, line x-y-2=0 divide the line segment joining (3,-10) and (8,9) in the ratio 11 :3.