Question

determine the ratio in which the x axis divide the line segment joining the points 2, - 3 and 5, 6 also find the coordinates of point of division ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

ANSWER

Let the required ratio be \lambda ;1.λ;1. Then, the coordinates of the point of division are,

R\left( \frac { 5\lambda +2 }{ \lambda +1 } ,\frac { 6\lambda -3 }{ \lambda +1 } \right)R(

λ+1

5λ+2

,

λ+1

6λ−3

)

But, it is a point on x-axis on which y-coordinates of every point is zero.

\therefore \quad \quad \frac { 6\lambda -3 }{ \lambda +1 } =0\Rightarrow \lambda =\frac { 1 }{ 2 }∴

λ+1

6λ−3

=0⇒λ=

2

1

Thus,the required ratio is \frac { 1 }{ 2 } :1\quad or,1:2.

2

1

:1or,1:2.

Putting \lambdaλ=1/2 in the coordinates of R, we find that its coordinates are (3,0)(3,0)

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