determine the ratio of lowest resistance that can be secured by combining four coils of resistance 2ohm, 4ohm, 8ohm, 12ohm
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Answer:please mark my answer as brainliest
Explanation:
If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by
1/R=1/R1 +1/R2+1/R3+1/R4
1/R=1/4+1/8+1/12+1/24
1/R=6+3+2+1/24
1/R=12/24
1/R=1/2
⇒R=2 Ω
∴ 2 Ω is the lowest total resistance
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