determine the rational no p and q if 7+ root 5/7-root 5 - 7-root 5/7+root 5=p-7root 5q
Answers
Answered by
7
Well, first you need to simplify your expression.
How ?
Simple! By rationalising.
(7+√5)/(7-√5) - (7-√5)/7+√5)
Rationalise both the terms
(7+√5)² - (7-√5)²/ 49 - 5
= 49 + 14√5 + 5 - 49 + 14√5 - 5/ 44
= 28√5/44
= 7√5/11
Now, 7√5/11 = a + (7/11) √5b
On comparison,
a = 0
b = 1
How ?
Simple! By rationalising.
(7+√5)/(7-√5) - (7-√5)/7+√5)
Rationalise both the terms
(7+√5)² - (7-√5)²/ 49 - 5
= 49 + 14√5 + 5 - 49 + 14√5 - 5/ 44
= 28√5/44
= 7√5/11
Now, 7√5/11 = a + (7/11) √5b
On comparison,
a = 0
b = 1
hkjain04:
but according to the given answer value of q is 1/11
Answered by
1
Answer p=0 and q=11/4
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