determine the refractive index of benzene if the critical angle is 42°
Answers
Answered by
255
Refractive index of benzene (n) = 1/ sinc
n=1/sin 42°
=1/0.6691
=1.51
therefore refractive index of benzene is 1.51
n=1/sin 42°
=1/0.6691
=1.51
therefore refractive index of benzene is 1.51
Answered by
153
Hi mate here is your answer
Given:-
The critical angle of benzene = 42
The refractive index of benzene (n) = 1 / sinc
n = 1 / sin 42
n = 1 / 0.6691
n = 1.51
Hope it may help you
The refractive index of benzene = 1.51
Given:-
The critical angle of benzene = 42
The refractive index of benzene (n) = 1 / sinc
n = 1 / sin 42
n = 1 / 0.6691
n = 1.51
Hope it may help you
The refractive index of benzene = 1.51
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